an elastic collision.,Ĭollisions between billiard balls are essentially elastic collisions. the balls un-deformation converted 100% of the energy from the deformation back into mechanical energy. Note that this result depends on the assumption $\Delta H = 0$ i.e. That is, Ball 1 will have been decelerated to $$. However, after a certain amount of time, both balls will have the same amount of momentum in the same direction. Since they have the same mass, Ball 1 will decelerate at the same rate Ball 2 accelerates. In this way, momentum is conserved, so that for any amount of momentum that Ball 2 gains, Ball 1 loses. In other words, Ball 1 exerts the same force on Ball 2 that Ball 2 exerts on Ball 1. Once Ball 1 hits Ball 2, it immediately starts accelerating it at the same rate that it decelerates. The balls have equal mass.īall 1 is the hitting ball, with an original velocity of $V_1$, and Ball 2 is getting hit, originally stationary. Let's say we have 2 balls, Ball 1 and Ball 2. However, now that I am thinking about it, I am a little confused as to how it is possible. I understand that this agrees with conservation of momentum. If 2 billiard balls are the same exact mass, and one hits another stationary one head on, I have heard that the hitting ball will often stop entirely while the one which got hit will go off at the original velocity of the first one ( ignoring friction and heat and other potential loss of energy). ( I'm repeating myself a lot here, but it's because I want to make my confusion clear.)
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